5x^2+4x-112=0

Solution for 5x^2+4x-112=0 equation:

5x^2+4x-112=0

a = 5; b = 4; c = -112;
Δ = b2-4ac
Δ = 42-4·5·(-112)
Δ = 2256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2256}=\sqrt{16*141}=\sqrt{16}*\sqrt{141}=4\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{141}}{2*5}=\frac{-4-4\sqrt{141}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{141}}{2*5}=\frac{-4+4\sqrt{141}}{10}
$